In the system shown find the initial acceleration of the wedge of mass 5m
Answers
Answer:
Acceleration of 5M block is 2g/23
Explanation:
Concept of Pseudo force is involved in this question....
Free body diagram in pdf attached at the bottom.
Let acceleration of 5M block be " b " and of M and 2M be " a ".
For 2M block,
2Mg - T=2Ma.................................1
N=2Mb............................2
For M block,
T + Mb=Ma.................3
N1 = Mg......................4
For 5M block,
T + N2= N1+ 5Mg....................5
T- N = 5Mb.......................6
From 2 and 6
T=7Mb..........................7
From 7 and 5
7Mb + N2 = 6Mg...........................8
From 3,
T + Mb=Ma
Ma=8Mb
b=a/8...........................9
Put values of N and N1 in 5 [N1 = Mg] and [N=2Mb]
2Mg + M = 3Ma
2g+b=3a
From 9,
2g +b=3(8b) [b=a/8]
2g-=23b
b=2g/23
This question requires a lot of patience, concentration and lot of concepts are involved in it. Be patient while reading the answer.