Question

●●●In the system shown in the figure, the acceleration of the 1 kg mass and the tension in the string connecting between A and B is

Answer 1

Answer:

Tension=

$\frac{2m1m2g}{m1 + m2}$

Therefore in this string tension is 240/7

Answer 2

Answer:

8mg/7.

Explanation:

The net force for the entire pulley system will be Fnet=3+1 -3 = 1g. Since the weight of 3g and g is greater than the 3g for the other block on the right side.

The net mass will be Mnet=3+1+3=7g so the acceleration a will be Fnet/Mnet = 1/7=g/7 m/s^2.

So, the tension in the string will be T=mg+ma which will be T=m(g+g/7) which on solving we will get 8mg/7 which will be the tension in the string.