Question

In the system shown the blocks a b and c of weight 4w, w and w respectively.the system is set free. the tension in the string connecting blocks b and c is.​

Answer 1

Answer:

if pulley is not rorate 4w/3

Explanation:

if tenson in bc rope. is t1

c block eq.

t1-w=wa/g

b block eq.

t2-t1-w=wa/g

a block eq

4w-t2=4wa/g

Answer 2

The tension in the string connecting blocks b and c is w(a+g)/g.

Given:-

Mass of Block a = 4w

Mass of Block b = w

Mass of Block c = w

To Find:-

The tension in the string connecting blocks b and c.

Solution:-

We can easily find out the tension in the string connecting blocks b and c by using these simple steps.

As

Mass of Block a = 4w

Mass of Block b = w

Mass of Block c = w

Weight of Block c = w

The tension between b and c = T =?

According to the formula for the tension in the string,

Weight - Tension = m × a

$w - T = \frac{w}{g} \times a$

$w - T = \frac{w \times a}{g}$

$T = \frac{wa}{g} + w$

$T = \frac{wa + wg}{g}$

$T = \frac{w(a + g)}{g}$

Hence, the tension in the string connecting blocks b and c is w(a+g)/g.

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