Question

In the time period of oscillation of a pendulum is measured as 2.5 second using a stopwatch with the least count 1/2 second, then the permissible error in the measurement is ??????​

Answer 1

Answer:-

Explanation:

Here T = 2.5s and ∆T = 0.5 s

so, the permissible error is :-

∆T/T×100% = (0.5/2.5)×100% =20%