In the trapezium ABCD, AB || DC, AB = 9 cm, DC = 6 cm and BD = 12 cm. The diagonals AC and BD intersect at O. Find the length of BO
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Answer:
first we have to make a equation :
BO + OD /BO = 9+6/9
12/BO= 15/9
108 /15 = Bo
Bo = 7.2cm
so we get Bo = 7.2 cm
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