in the triangle ABC AB is equal to AC ad is the angular bisector of angle A B AC meeting BC in dene prove that ad is equal to BC and BD is equal to CD
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1) As AD is the bisectoe of angle A
therefore,
angle BAD = angle DAC
hence,
BD=DC (sides opposite to equal angles are equal)..........(i)
Now,
BD+DC=BC
BD+BD=BC (from (i))
2BD=BC
therefore,
D is the midpoint of BC.......(A)
And AD is the bisector of BC..........(B)
from,
(A) and (B)
Hence proved
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