In the triangle ABC, angle A= 90° and AD⊥BC. If AB= 6cm, AC = 8cm and BC= 10cm. Then find length of CD
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Answer:
In △ABC,∠B=90
o
∴ By Pythagoras theorem,
AC
2
=AB
2
+BC
2
AC
2
=6
2
+8
2
∴AC
2
=36+64=100
∴AC=10cm
ii) In △ABC,∠B=90
o
∴ By Pythagoras theorem,
AC
2
=AB
2
+BC
2
13
2
=AB
2
+5
2
∴AB
2
=169−25=144
∴AB=12cm
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