Question

In the triangle ABC, PQ II BC.
AC=30 ft Q C=20 ft, AB=12 ft, find AP​

Answer 1

Answer:

In figure (i), we have

PQ∣∣BC

Therefore, by basic proportionality theorem, we have

PB

AP

=

QC

AQ

⇒

3

1.5

=

QC

1.3

⇒

2

1

=

QC

1.3

⇒ QC=2.6cm

In figure (ii), it is given that PQ∣∣BC.

Therefore, by basic proportionlity theorem, we have

PB

AP

=

QC

AQ

⇒

6

3

=

5.3

AQ

⇒

2

1

=

5.3

AQ

⇒ AQ=

2

5.3

=2.65cm