Question

In the triangle PQR angle Q is an right angle.PQ is 12cm and PR is 13cm.we have to find value of tanP-cotR

Answer 1

$\textbf{Given:}$

$\text{In right angled \triangle PQR, PQ=12 cm and PR=13 cm}$

$\textbf{To find:}$

$tan\,P-cot\,R$

$\textbf{Solution:}$

$\text{In right angled \triangle PQR, by Pythagoras theorem}$

$\text{we get}$

$PR^2=PQ^2+QR^2$

$13^2=12^2+QR^2$

$169=QR^2+144$

$\implies\,QR^2=25$

$\implies\,QR=5$

$\text{Consider,}$

$tan\,P=\dfrac{QR}{PQ}$

$\implies\bf\,tan\,P=\dfrac{5}{12}$

$cot\,R=\dfrac{QR}{PQ}$

$\implies\bf\,cot\,R=\dfrac{5}{12}$

$\text{Now,}$

$tan\,P-cot\,R$

$=\dfrac{5}{12}-\dfrac{5}{12}$

$=0$

$\therefore\textbf{The value of tan\,P-cot\,R is 0}$

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If triangle ABC And right angle at c then the value of cosec(A +B)

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Answer 2

Answer:

hi

Step-by-step explanation: