in the triangle PQR ,PQ=6.4mm,RQ=4.8mm and PQ=6mm find the area of triangle PQR find the height corresponding to PQ.
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Hello,
The height can be taken out by taking the triangle PRS. It is a right angled triangle and we are given the length of one of its leg and the hypotenuse. So we can take out the length of RS by pythagoras theorem.
It is a²+b²=c²
A and B are legs and C is hypotenuse.
So 3.2²+x²=6²
10.24+x²=36
x²=36-10.24
x²=25.76
x=5.07
Height RS=5.07
Now, the area of a triangle is 1/2*b*h
b=6.4
h=5.07
Area= 1/2*6.4*5.07=3.2*5.07=16.224
Area of the triangle PQR=16.224
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