Question

In the visible region of the spectrum the rotation of the place of polarization is given by$\theta= a+ \frac{b}{\lambda^2}$ . The optical rotation produced by a particular material is found to be 30° per mm at $\lambda = 5000 \AA$ and 50° per mm at [tex] \lambda = 4000 \AA [/tex. The value of constant a will be
(a) $+ \frac{50\textdegree}{9}$ per mm
(b) $- \frac{50\textdegree}{9}$ per mm
(c) $+ \frac{9\textdegree}{50}$ per mm
(d) $- \frac{9\textdegree}{50}$ per mm

Answer 1

hey..
where is ur option A ...

option correct is B.....

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