Question

In this figure BC is based on ABC and DBC Triangles . so we need to prove <ABD = <ACD ​

Answer 1

Answer:

In triangle ABC

AB=AC

angle ABC=angle ACB ---------(1)

In triangle BCD

BD=CD

angle DBC=angle DCB --------------(2)

Adding (1) and (2) we get

ABC+DBC=ACB+ DCB

angle ABD=angle ACD

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