Question

In this figure,st//rq,ps=3cm and sr=4cm.find the ratio of the area of ∆pst to the areaof ∆prq

Answer 1

area of ∆pst/area of ∆prq= (3/4)power2 = 9/16

Answer 2

Answer:

9:49

Step-by-step explanation:

Given

ST || RQ

PS= 3 cm

SR = 4cm

Proof :--

ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49