in this given figure AB //CD&CA= CE find the values of x,y,z
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using alternate interior angle we get<X=<EDC
so<X=36
now in ∆aec CA=CE
so <cae= <aec
now using triangle sum Pro in triangle ced we get<ced=112
also<AEC+<ced=180
so <AEC=68=y
then using triangle sum in ace
z=44
so X=36.
y=68
z=44
so<X=36
now in ∆aec CA=CE
so <cae= <aec
now using triangle sum Pro in triangle ced we get<ced=112
also<AEC+<ced=180
so <AEC=68=y
then using triangle sum in ace
z=44
so X=36.
y=68
z=44
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