In this given figure, AD divides angle BAC in the ratio 1:3 and AD=DB.
Determine the value of x.
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aman200419:
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Step-by-step explanation:
Let angle BAD be x and angle CAD be 3x.
Then, angle EAC + angle CAD + angle BAD = 180 ...... (straight angle)
=> 108+3x+x = 180
=> 4x+108 = 180
=> 4x = 180-108
=> x = 72/4
Therefore, x = 18
So, angle BAD = 18° and angle CAD = 3×18
= 54°
and angle BAC = 54+18
= 72.
Now, AD = DB ....(given)
Therefore, angle ABC = angle BAD
So,angle ABC = 18
And in ∆ABC,
angle ABC + angle BAC + angle ACB = 180 (linear pair)
=> 18+72+x = 180
=> x = 180 - 90
Hence, x = 90°
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