Question

If cos theta = 1/2 Find sec square theta + tan square theta / 7-2 sec theta cosec theta

Answer 1

this is your answer of your question

Answer 2

Answer:

(13√3)/(28-32√3)

Step-by-step explanation:

given cos α= 1/2

then sec α=2

and tan²α=sec²α-1=1/4-1= -3/4

we know sin²α+cos²α=1

⇒sin α=√3/2

so cosec α=2/√3

so

sec²α+tan²α / 7-2sec α* cosec α

⇒4+(-3/4) / 7- 2*2*2/√3

⇒13/4 / 7- 8/√3

⇒(13√3)/(28-32√3)