In this question,if the sizes of the interior angles of a pentagon are2x,3x,4x,5x and 6x ,find the largest interior angles of the pentagon the answer x is 27 and then 6(27) ,how did the 6 come?
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Answered by
1
Step-by-step explanation:
- 2x+3x+4x+5x+6x=180
- 20x=180
- x=180/20
- x=9
- the largest interior angle is
- 6x= 6X9=54
Answered by
0
Answer:
sunm of all angles of a pentagon =540°
2x+3x+4x+5x+6x=540°
20x=540°
X=540/20
X=27
largest interior angle =6(27)=162
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