in this question we have to find ANGLE:1,2,3
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CE||AB therefore angle BAC equals to angle ACE.
Therefore angle 1 =75°
Now in a straight line the angle is 180°.
BCD is a straight line therefore,
angleBCD= angle 3+ angle 1 +angle ACB
180°= angle 3+75°+40°
angle 3 = 180°-75°-40°= 65°
Now in a triangle the sum of interior angle is 180°.
Therefore
180°=angle3+angle2+angle BAC
180°= 65° +angle2 +75°
angle2=180°-65°-75°=180°-140°=40°
Therefore the required angles 1,2and3 are 75°,40°and 65° respectively.
Therefore angle 1 =75°
Now in a straight line the angle is 180°.
BCD is a straight line therefore,
angleBCD= angle 3+ angle 1 +angle ACB
180°= angle 3+75°+40°
angle 3 = 180°-75°-40°= 65°
Now in a triangle the sum of interior angle is 180°.
Therefore
180°=angle3+angle2+angle BAC
180°= 65° +angle2 +75°
angle2=180°-65°-75°=180°-140°=40°
Therefore the required angles 1,2and3 are 75°,40°and 65° respectively.
nishu3030:
thks ssssssomuch
please mark as the brainliest
I will surely do it but we need two answers to mark answers brainliest.
so u can challenge ur followers to do dis question so that there are 2 answers and then i ll mark it brainliest.
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