Question

In three vessels of 10l capacity, mixture of milk and water is filled. The ratio of milk and water are 2 : 1, 3 : 1 and 3 : 2 in the respective vessels. If all the three vessels are emptied into a single large vessel, find the ratio of milk and water in the resultant mixture.

Answer 1

••• Step - 1 •••

• Capacity of 1st vessel = 10 l

  Milk : Water = 2 : 1

  Ratio sum = 2 + 1 = 3

  Milk = (2/3) × 10 = (20/3) l

  Water = (1/3) × 10 = (10/3) l

• Capacity of 2nd vessel = 10 l

  Milk : Water = 3 : 1

  Ratio sum = 3 + 1 = 4

  Milk = (3/4) × 10 = (15/2) l

  Water = (1/4) × 10 = (5/2) l

• Capacity of 3rd vessel = 10 l

  Milk : Water = 3 : 2

  Ration sum = 3 + 2 = 5

  Milk = (3/5) × 10 = 6 l

  Water = (2/5) × 10 = 4 l

••• Step - 2 •••

Now, three vessels are emptied into a single large vessel.

  Total capacity = (10 + 10 + 10) = 30 l

  Milk = (20/3) + (15/2) + 6 = (121/6) l

  Water = (10/3) + (5/2) + 4 = (59/6) l

Milk : Water = (121/6) : (59/6) = 121 : 59

Answer 2

Answer:

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