Question

In thw above figure find <x.Further find <BOC,<COD and <AOD​

Answer 1

Here is ur answer⤵

x+x+10°+x+20°=180°

3x+30°=180°

3x=180°-30°

3x=150°

x=150°/3

x=50°

x+10°=50°+10°

x+10°=60°

x+20°=50°+20°

x+20°=70°

Hope it helps..✌

Stay safe..✨

Keep smiling..☺

Answer 2

Answer:

x = 50°

Angle BOC = 70°

Angle COD = 50°

Angle AOD = 60°

Step-by-step explanation:

(x+10) + x + (x+20) = 180 (Angles on a straight line = 180)

3x + 30 = 180

3x = 180 - 30 = 150

x = 150/3 = 50°

x = 50°

Angle BOC = x + 20 = 50 + 20 = 70°

Angle BOC = 70°

Angle COD = x = 50°

Angle COD = 50°

Angle AOD = x + 10 = 50 + 10 = 60°

Angle AOD = 60°

Hope it helps you:)