Question

in traiangle ABC ,DE parallel BC , AD =X ,DB =X-2 ,AE =X+2 and EC=X-1 find the value of x​

Answer 1

Answer:

x=4

Step-by-step explanation:

• you should use similarity of triangles formula to find the answer so
• using proportionality theorem we find x=4
• $\frac{AD}{AB} = \frac{AE}{AC\\}$

Answer 2

Given, DE//BC

$\frac{AD}{DB} = \frac{AE}{EC} \\ \\ \frac{x}{x -2 } = \frac{x + 2}{x - 1} \\ \\ x(x - 1) = (x + 2)(x - 2) \\ \\ {x}^{2} + x = {x}^{2} + 4 \\ \\ x = 4$