Question

In traingle ABC, the bisector AD of angle A is perpendicular to side BC. Show that AB=AC and traingle ABC is a isosceles.​

Answer 1

Answer:

I hope it helps u.........nd sorry for cutting.......

Answer 2

$\large\sf{In\:∆ABD\:and\:∆ACD}$

$\large\sf{\angle{BAD}=\angle{CAD}(given)}$

$\large\sf{AD=AD(common)}$

$\large\sf{\angle{ADB}=\angle{ADC}=90°(given)}$

$\therefore$$\large\sf{∆ABD\:\cong\:∆ACD}$

$\large\sf{By\:ASA\:congruence\:rule}$

$\large\sf\red{And,}$

$\large\sf{AB=AC(CPCT)}$