Question

in traingle pqr , <q =90° and Qm is perpendicular to pr. prove that:
1, pq 2 = pm* PR

2, Qr 2 = PR*Mr

3, pq 2 + Qr 2 = PR 2

pls urgent

Answer 1

in triangle pqm and triqngke pqr
angle qmp=<pqr. 90
<p=<p. commn
triangle pqm ~pqr AA

pq/pr=pm/pq
so pq2=pm*pq


triangle qrm a.d pqr

angle qmr=<q 90
ang r=r
qmr~pqr. AA

qr/pr =mr/qr

qr2=pr*mr



adding 1 and 2

pq2+qr2 =pm*pr+pr*mr

pr(pm+mr)=pr(pr)=pr2


hope this helps....

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