Question

In traingle PQR PQ=7cm <P=50° <Q=60° cunstruct the traingle​

Answer 1

Answer:

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1) Draw the base QR = 6 cm.

At point Q draw a ray QX making an ∠ QXR = 60o.

Here, PR-PQ = 2cm

PR > PQ

The side containing the base angle Q is less than third side.

2) Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.

3) Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

4) Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.

Thus, △ PQR is the required triangle.

Answer 2

Step-by-step explanation:

first draw base PQ=7cm then with protracter Mark 50 degrees at P and 60 degrees at Q and then extend those lines you will get your point R

hope it helps you

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