Question

in traingleabc,angle b=90;ab:bc=3:4,then cos a is =?

give correct answer only
do not spam
show steps too​

Answer 1

According to question,

$↬ {ac}^{2} = {ab}^{2} + {bc}^{2} \\ {ac}^{2} = {3}^{2} + {4}^{2} \\ {ac}^{2}= 9 + 16 \\ {ac}^{2} = 25 \\ ac = \sqrt{25} \\ ac = 5$

$so \: \cos(a) = \frac{perpendicular}{hypotenuse} \\ \\ \cos(a) = \frac{3}{5}$

Hope it may help uh

Answer 2

Above the answer is correct
I can’t write like that as sent above so I’m saying
Mark me as brainliest