Question

solve the attached questions....​

Answer 1

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Answer 2

Answer:

y = √[log{sin(x²/3-1)}] , find dy/dx

x³/3-1 = u suppose that

.

Sin u = v suppose that..

log v = w suppose that

y = √w

Dy/dw = 1/2√w

dw/DV = 1/v

DV /du = cosu

du /DX = 2x/3

Dy /DX = dy / dw × dw/dv × DV/du × Du/dx

= 1/2√w × 1/v × cos u× 2x/3

Dy/DX = xcot (x²/3-1)/3 1/[log { sin(x²/3 -1)]¹/²