In trangle abc ab=ac=10cm m is the mid point of bc bm=6cm find the lenth of am
and what is the
area of trangle abm
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AM sq. = AM sq + BM sq.
10sq. = AMsq. + 6sq.
100 = AMsq. + 36
100-36=AMsq.
64=AMsq.
(8)sq.= AMsq
8= AM
BC= 6+6=12 (as M is the mid point)
Area of triangle ABC=1/2(Base × Altitude )
1/2 (12×4)
=48cm
10sq. = AMsq. + 6sq.
100 = AMsq. + 36
100-36=AMsq.
64=AMsq.
(8)sq.= AMsq
8= AM
BC= 6+6=12 (as M is the mid point)
Area of triangle ABC=1/2(Base × Altitude )
1/2 (12×4)
=48cm
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