Question

In trapezium a b c d , ab angle is parallel to CD and if angle a is equal to 50 angle b is equal to 70 find angle b and angle d

Answer 1

$\huge{\tt{\red{}\green{A}\purple{N}\pink{S}\blue{W}\orange{E}\red{R}}}☘$

ABCD is a trapezium

AB||CD and BC is transversal

Angle B + Angle C = 180

Angle C=180-70

=110

Similarly,

ANGLE D = 180-50=130

So, Angle C= $\fbox\red{110°}{}$

Angle D= $\fbox\red{130°}{}$

Answer 2

It is given that AB || DC

From the figure we know that ∠ A and ∠ D are consecutive interior angles

So it can written as ∠ A + ∠ D = 180

To find ∠ D

∠ D = 180° – ∠ A

By substituting the value in the above equation ∠ D = 180° – 55°

By subtraction ∠ D = 125°

In a quadrilateral we know that the sum of all the angles is 360°

So we can write it as ∠ A + ∠ B + ∠ C + ∠ D = 360°

By substituting the values in the above equation 55° + 70° + ∠ C + 125° = 360°

On further calculation

∠ C = 360° – 55° – 70° – 125°

By subtraction ∠ C = 360° – 250°

∠ C = 110°

Therefore, ∠ C = 110° and ∠ D = 125°

Hope this helps you ❤️