In trapezium ABCD, AB||DC find angle c and d
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Answered by
1
Answer:
c is 90 degree
d is 125 degree
Answered by
13
Answer:
it is given that AB || DC
and angle B is given as 90°
so we can say that angle C will be also 90°
in a quadrilateral of 4 vertices the sum of the angle = 360
55° + 90° + 90° + D = 360°
235° + D = 360°
D = 360° - 235°
D = 125
therefore angle C = 90 and angle D = 125
I think this is the answer ............. I hope it helps you
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