Question

In trapezium ABCD, AB is parallel to CD and EF IS median. DC=6cm, EF=4cm,then AB is?

Answer 1

To find CD, we need to get the segments DP and CQ, which is possible by applying Pythagoras theorem:

AD^2 = AP^2 + DP^2

13^2 = 12^2 + DP^2

169 = 144 + DP^2

Hence, DP = 5

Similarly, BC^2 = BQ^2 + CQ^2

15^2 = 12^2 + CQ^2

225 = 144 + CQ^2

Hence, CQ = 9

Required length, CD = DP + PQ + CQ = 5 + 20 + 9 = 34