In trapezium ABCD, AB is parallel to CD. Diagonals AC and BC intersect at 'O' . Prove that triangle AOB is similar to triangle COD.
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Step-by-step explanation:
angle AOB=angle COD(vetically opp angles)--------------1
angleBAC=angleACD(alternate interior angles)--------------2
by AAsimilarity triangleAOB SIMILAR TO triangle DOC
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