Question

The values of current (I) flowing through a given resistor of resistance (R), for the corresponding values of potential difference (V) across the resistor are as given below:V (volts) 0.5 1.0 1.5 2.0 2.5 3.0 4.0 5.0I (amperes) 0.1 0.2 0.3 0.4 0.5 0.6 0.8 1.0

Answer 1

V - I graph as shown in figure . Here points lie on the equation of line {where variables are V and I } are (1.6 ,0.5) , (3.4,1.0) , (6.7, 2.0) , (10.2, 3.0) and (13.2, 4.0)

Now , use Ohm's law ,

V = IR

R = V/I , means Resistance is the slope of graph V - I

So, R = (V₂ - V₁)/(I₂ - I₁)

V₂ = 3.4V, V₁ = 1.6V , I₂ = 1A and I₁ = 0.5A

So, R = (3.4 - 1.6)/(1 - 0.5) = 1.8/0.5 = 3.6

Hence, resistance , R = 3.6Ω

similarly R= (V₃ - V₂)/(I₃ - I₂) = (6.7 - 3.4)/(2 - 1) = 3.3

R = (V₄ - V₃)/(I₄ - I₃) = (10.2 -6.7)/(3-2) = 3.5

R=(V₅ - V₄)/(I₅ - I₄) = (13.2 - 10.2)/(4-3) = 3

here R is variable so, take average of all . Rav = (3.6 + 3.3 + 3.5 + 3)/4 = 13.4/4 = 3.35Ω

hence, resistance = 3.

Answer 2

Answer:

hey mates

here is your answer

V - I graph as shown in figure . Here points lie on the equation of line {where variables are V and I } are (1.6 ,0.5) , (3.4,1.0) , (6.7, 2.0) , (10.2, 3.0) and (13.2, 4.0)

Now , use Ohm's law ,

V = IR

R = V/I , means Resistance is the slope of graph V - I

So, R = (V₂ - V₁)/(I₂ - I₁)

V₂ = 3.4V, V₁ = 1.6V , I₂ = 1A and I₁ = 0.5A

So, R = (3.4 - 1.6)/(1 - 0.5) = 1.8/0.5 = 3.6

Hence, resistance , R = 3.6Ω

similarly R= (V₃ - V₂)/(I₃ - I₂) = (6.7 - 3.4)/(2 - 1) = 3.3

R = (V₄ - V₃)/(I₄ - I₃) = (10.2 -6.7)/(3-2) = 3.5

R=(V₅ - V₄)/(I₅ - I₄) = (13.2 - 10.2)/(4-3) = 3

here R is variable so, take average of all . Rav = (3.6 + 3.3 + 3.5 + 3)/4 = 13.4/4 = 3.35Ω

hence, resistance = 3.

I hope this answer help you

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