Question

In trapezium ACBD, side AB || side DC, diagonals AC and BD intersect in point p. Show that AP/PD BP/PC​

Answer 1

Answer:

I don't understand this

Step-by-step explanation:

Answer

From the picture we have Δ COD is similar to Δ AOB.

Since, ∠COD=∠AOB (opposite angle) , ∠CDO=∠OBA (transversal angle) and ∠DCO=∠OAB (transversal angle).

Then

AB

CD

=

OA

OD

or,

20

6

=

15

OD

or, OD=4.5