Question

In trapezium PQRS side PQ is parallel to side SR , AR = 5AP, AS =5AQ then prove that , SR = 5PQ

Answer 1

$\large{\mathbf{HELLO \: \: DEAR,}}$

$\mathit{GIVEN \: \: THAT:-} \\ \\ \mathit{PA || SR , AR = 5AP , AS = 5AQ,} \\ \\ \mathit{WE \: \: HAVE \: \: TO \: \: PROVE :- SR = 5PQ} \\ \\ \mathit{IN \: \: \triangle APQ , \: \: AND \: \: \triangle \: ARS} \\ \\ \mathit{\angle 1 = \angle 4 [ vertical \: \: opposite]} \\ \\ \mathfrak{\angle 2 = \angle 6 [ alt. interior]} \\ \\ \mathfrak{\angle 3 = \angle 5 [ alt . \: \: interior]} \\ \\ \mathit{hence , \: \: \triangle APQ \sim \triangle ARS \: \: (by A.A.A)} \therefore , \frac{AP}{AR} = \frac{PQ}{RS} = \frac{AQ}{AS} \frac{AP}{5AP} = \frac{PQ}{RS}$


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Answer 2

Answer:

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