in tri ABC,if angle A=65°;angle B=40° then find the measure of angle C
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sum of all angles of tri.=180
a+b+c=180
65+40+c=180
c=180-105
c=75
a+b+c=180
65+40+c=180
c=180-105
c=75
Answered by
0
we know that sum of all the angles of a triangle is 180°
angleA+angleB+angleC=180°
65°+40°+angleC=180°
105°+angeC=180°
angle C =180°-105°
=75°
angleA+angleB+angleC=180°
65°+40°+angleC=180°
105°+angeC=180°
angle C =180°-105°
=75°
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