Question

In triangle ABC,A(3,5),B(7,8)and C(1,10)are the vertices .find the equation through median A

Answer 1

Step-by-step explanation:

let AD be the median through A  

since AD is median

BD = CD

therefore co-ordinates of D will be =[ (7+1)/2 , (8+(-10))/2 ]

                                                      =[ 4 , -1 ]

therefore equation of AD in two point form will be  

(y-y1) / (y1-y2) = (x-x1) / (x1-x2)                .......(were y1=5 , y2=-1 ,  

                                                                                    x1=3 , x2=4

:- (y-5) / 6 = (x-3) / (-1)

:- -y + 5 = 6x - 18

:- 6x + y = 23

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Answer 2

Answer:

6x + y - 23 = 0

Step-by-step explanation:

Let D be the median

Coordinates of D = (7+1/2 , 8-10/2) = (8/2 , -2/2)

Coordinates of D = (4 , -1)

Slope of AD = (-1-5)/(4-3) = -6

Equation of AD = y - 5 = -6 (x - 3)

y - 5 = -6x + 18

6x + y - 23 = 0