In triangle ABC, A=(3,5), B=(7,8) and C=(1,-10). Find the equation of the median through A. Pls solve it(Ans:6x+y=23) pls show each step...
Answers
Answered by
125
ḷet AD be the median through A
since AD is median
BD = CD
therefore co-ordinates of D will be =[ (7+1)/2 , (8+(-10))/2 ]
=[ 4 , -1 ]
therefore equation of AD in two point form will be
(y-y1) / (y1-y2) = (x-x1) / (x1-x2) .......(were y1=5 , y2=-1 ,
x1=3 , x2=4
:- (y-5) / 6 = (x-3) / (-1)
:- -y + 5 = 6x - 18
:- 6x + y = 23
since AD is median
BD = CD
therefore co-ordinates of D will be =[ (7+1)/2 , (8+(-10))/2 ]
=[ 4 , -1 ]
therefore equation of AD in two point form will be
(y-y1) / (y1-y2) = (x-x1) / (x1-x2) .......(were y1=5 , y2=-1 ,
x1=3 , x2=4
:- (y-5) / 6 = (x-3) / (-1)
:- -y + 5 = 6x - 18
:- 6x + y = 23
Answered by
0
Answer:
6x + y - 23 = 0
Step-by-step explanation:
Let D be the median
Coordinates of D = (7+1/2 , 8-10/2) = (8/2 , -2/2)
Coordinates of D = (4 , -1)
Slope of AD = (-1-5)/(4-3) = -6
Equation of AD = y - 5 = -6 (x - 3)
y - 5 = -6x + 18
6x + y - 23 = 0
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