Question

in triangle abc a b is equal to 3 cm AC is equal to 3 cm and angle A is equal to 50 degree find Angle B

Answer 1

AB = AC

∠B =∠ C

∠A + ∠B + ∠C = 180°

50° + ∠B +∠B =180°

2∠B = 130°

∠B = 65°

Answer 2

Since two sides are equal ∆ABC is an isosceles ∆.
i.e. /_B = /_C = x (say)
Then,
/_A + /_B + /_C = 180°
=> 50° +x +x = 180°
=> 2x = 180° - 50°
=> 2x = 130°
=> x = 130°/2 = 65°
Therefore /_ B = 65°