Question

in triangle ABC A-D-B CD=6 BD=9 BC=12.If angle CAD=angle BCD Then find perimeter of triangle ADC
Pls solve this ASAP​

Answer 1

Area of ΔADB = 19.5 cm²

Step-by-step explanation:

Given : AB = 12 cm. BC = 6.5 cm.

In the ΔABC, ∠ABC = 90°.

Since AD = DC, D is the midpoint of AC.  So BD is the median.

AB ⊥ BC.

Now, since BD is the median it divides the ΔABC into two equal parts.

2 × Ar(ΔADB) = Ar(ΔABC) 

⇒ 2 × Ar(ΔADB) = 39

⇒ Area of ΔADB = 19.5 cm²