Question

In triangle ABC, a line parallel to the side BC cuts the side AB and AC in the points X
and Y respectively such that AX = 12, XB = 8 and AY = 9. Find YC.



please give answer urgent don't fake please
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Answer 1

Answer:

In triangle ABC, a line parallel to the side BC cuts the side AB and AC in the points X and Y respectively such that AX = 12, XB = 8 and AY = 9.

$\\ \frac{ax}{xb} = \frac{yc}{cb} \\ \frac{12}{8} = \frac{yc}{9} \\ yc = \frac{3}{2} \times 9 = \frac{27}{2} = 13.5$