in triangle abc ab= 4 cm bc= 9 cm and ac=7 cm .find the length of the perpendicular from a to bc
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Step-by-step explanation:
Using the cosine rule in Tr. ABC, cos(B)=(9²+7²-8²)/(2*9*7)=11/21. Since AB//DC we can say that cos(C) = - cos(B) = - 11/21. Now use the cosine rule once again in Tr. BCD to claim that: cos(C)= -11/21 = (9²+7²-x²)/(2*9*7) which yields, x =14 cm.
biswasneetu:
can u tell ans using herons formula
use heron's formula to find area then area = 1/2 b h
a but plz first brainlist please
then i will do so
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