In triangle abc ab=5cm ,ac=5cm and angle a =50degree then angle b= ?
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Answered by
85
Since, AB = AC = 5cm.It is an isosceles triangle.
Therefore, angleB = angleC (In an isosceles triangle the angles opposite to equal sides are also equal)
So, angleA+angleB+angleC = 180 (sum of all angles of a triangle is 180 degree)
50+angleB+angleB = 180° (angleA = angleB)
2angleB = (180-50)°
2angleB = 130°
angleB = (130/2)°
angleB = 65°
Therefore, angleB = angleC (In an isosceles triangle the angles opposite to equal sides are also equal)
So, angleA+angleB+angleC = 180 (sum of all angles of a triangle is 180 degree)
50+angleB+angleB = 180° (angleA = angleB)
2angleB = (180-50)°
2angleB = 130°
angleB = (130/2)°
angleB = 65°
Answered by
10
Answer:
65⁰
Step-by-step explanation:
65 degree
hope it helps
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