In triangle abc ab=5cm bc=8cm CA=7 cm d and e are respectely the mid points ab and bc find de
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de is the half of ac by mid point theorm so de=1/2bc so de=4
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Answer:
In ΔABC, we have AB = 5cm, BC = 8 cm and CA = 7 cm. Since, D and E are the mid-points of AB and BC, respectively.
By mid-point theorem, DE || AC
and
DE = 1/2 AC = 7/2 = 3.5 cm
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