Math, asked by kiki6396, 10 months ago

In triangle abc ab=7√2,bc=14,ac=7 then find angle c

Answers

Answered by pixx

0

Answer:

it would be more clear if u cud send a photo of it

Answered by venkatavineela3

0

Answer:

Step-by-step explanation:

c^2 = a^2 + b^2 – 2ab cos C

(7sqrt(2))^2=(14^2)+(7^2)-2(14*7)cosC

98=196+49-196cosC

196cosC=196+49-98=147

cosc=147/196=3/4

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