In triangle ABC, AB=AC and AD is the bisector of angle A, PROVE THAT ) Traingle ABD is congruent to triangle ADC ii) AD is perpendicular to BC
Answers
Step-by-step explanation:
Given:-
- In ∆ABC AB = AC.
- AD is bisecting the angle A.
To prove:-
- ∆ABD is congruent to ∆ACD
- AD is Perpendicular to BC.
Prove:-
We know if any line bisect angle in two angles. Then angles are equal.
Here, AD is bisector of angle A.
So, ∠BAD = ∠CAD ----------(i)
In ∆ABD and ∆ACD.
✤ AB = AD [Given]
✤ ∠BAD = ∠CAD [By equation (i)]
✤ AD = AD [Common]
By SAS congruency,
• ∆ABD ≅ ∆ACD
Hence, Proved!!
__________________________________
Now,
By, CPCT
• ∠ADB = ∠ADC
Let,
• ∠ADB = ∠ADC = x
We know,
Sum of all angles forms on straight line is equal to 180°. We also say this statement be linear pair.
So,
So,
∠ADC = 90°
- We know, perpendicular means 90°.
Thus, AD is Perpendicular on BC.
Hence, Proved!!
In triangle ABC, AB=AC and AD is the bisector of angle A, PROVE THAT ) Traingle ABD is congruent to triangle ADC ii) AD is perpendicular to BC
In ∆ABC AB = AC.
AD is bisecting the angle A.
To prove:-
∆ABD is congruent to ∆ACD
AD is Perpendicular to BC.
Prove:-
We know if any line bisect angle in two angles. Then angles are equal.
Here, AD is bisector of angle A.
So, ∠BAD = ∠CAD ----------(i)
In ∆ABD and ∆ACD.
✤ AB = AD [Given]
✤ ∠BAD = ∠CAD [By equation (i)]
✤ AD = AD [Common]
By SAS congruency,
• ∆ABD ≅ ∆ACD
Hence, Proved!!
__________________________________
Now,
By, CPCT
• ∠ADB = ∠ADC
Let,
• ∠ADB = ∠ADC = x
We know,
Sum of all angles forms on straight line is equal to 180°. We also say this statement be linear pair.
So,
⇝∠ADB+∠ADC=180°
⇝x+x=180°
⇝2x=180°
⇝x= 2/180°
⇝ x=90°
So,
∠ADC = 90°
We know, perpendicular means 90°.
Thus, AD is Perpendicular on BC.
Hence, Proved!!