Question

In triangle abc ab=ac and angle acd=105°( exterior angle) find angle bac

Answer 1

Hey Here is your answer


If ab = ac than abc is a isosceles triangle

angle acb + angle acd = 180 ( angle on straight line )
angle acb + 105 = 180
angle acb = 75

We know that abc is a isosceles triangle
so angle abc = angle acb

Applying angle sum property
angle bac + angle acb + angle cba = 180
angle bac + 75 + 75 = 180
angle bac + 150 = 180
angle bac = 30

So angle bac is 30 degree


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