in triangle ABC,AB=AC and angle B =30 degree, find other two angles
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if AB=AC then ABC is an isosceles triangle
so, angle B = angle C ( base angles of a isosceles triangle are equal)
so, angle C =30°
and angle A = 180°-(30°+30°)
angle A = 180°-60°
=120° answer....
so, angle B = angle C ( base angles of a isosceles triangle are equal)
so, angle C =30°
and angle A = 180°-(30°+30°)
angle A = 180°-60°
=120° answer....
Nini81:
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Answered by
2
Here since AB = AC
angle B=angle C=30degree
(angles opposite to equal sides are equal)
angleA+angleB+angleC=180degree
(angle sum property of a triangle)
angleA+30+30=180
angleA=180-60
angleA=120
Therefore, angleA=120degree
angleB=30degree
angleC=30degree
angle B=angle C=30degree
(angles opposite to equal sides are equal)
angleA+angleB+angleC=180degree
(angle sum property of a triangle)
angleA+30+30=180
angleA=180-60
angleA=120
Therefore, angleA=120degree
angleB=30degree
angleC=30degree
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