in triangle abc ab=ac and d is a point on ab such that ad=dc=bc.then anglebac=?
tanishqsingh:
are u sure its ad=dc=bc?
okok..sry
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so according to fig.,
x=2y(ext. angle = sum of int. oppoite angles.)
so DBC=ACB=2y
so BAC+ABC+BCA=180
y+2y+2y=180
5y=180
y=180/5=36°
BAC=y=36°
x=2y(ext. angle = sum of int. oppoite angles.)
so DBC=ACB=2y
so BAC+ABC+BCA=180
y+2y+2y=180
5y=180
y=180/5=36°
BAC=y=36°
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i think, it's fine now.:)
hh great sorry that was my mistake!
no problem.:)
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