Question

In triangle ABC, AB = AC and the bisector of angle A intersects BC
at D prove that triangle ADB congruent triangle ADC.​

Answer 1

Step-by-step explanation:

AB=AC

BAD° = CAD°

AD= AD ( COMMON)

BY SAS CONGRUENCE RULE

∆ABD~= ∆ACD

Answer 2

Given: ΔABC AB=AC and bisector of ∠∠A intersect BC at D

To prove: Δ ADB ≅Δ ADC

Step-by-step explanation:

Consider Δ ADB and Δ ADC

AB= AC                           (Given)

∠BAD= ∠CAD                 (AD is bisector of ∠A)

AD= AD                           (Common)

Therefore

Δ ADB ≅ Δ ADC             (side -angle - side) criteria

Hence proved that Δ ADB ≅ Δ ADC