In triangle ABC , AB = AC , angle A = 2x° and angle B = x + 10°. Find the measures of all the angles of triangle ABC .
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given: AB = AC , ∠A = 2x°, ∠B = x + 10°.
to find: all the angles of the triangle ABC
- Since,
- A = 2x and B = x+10,
we can find the third angle using angle sum property of a triangle
- C = 180-(A+B)
putting values of A and B in C,
- C = 180-(2x + x + 10)
2. since AB = AC,
- so ∠ABC = ∠ACB (Angle same in front of same sides)
∴ x+10 = 180 - (2x + x + 10)
4x + 20 = 180
4x = 160
x = 40°
calculating all the values using x, we get
∠A = 2x= 2(40) = 80°
∠B = x+10 = 90°
∠C = 10°
A = 80°, B = 90°, C = 10°
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